1) Suppose 6 days after the day before yesterday is Thursday. What day of the week is the day after tomorrow?
2) There are 4 separate boxes, and inside each large box there are 3 separate small boxes, and inside each of these small boxes there are 2 separate smaller boxes. How many boxes, counting all sizes, are there altogether? 3) When asked how many gold coins he had, the collector said: If I arrange them in stacks of five, none are left over. If I arrange them in stacks of six, none are left over. If I arrange them in stacks of seven, one is left over. What is the least number of coins he could have? Solutions 1) Make a linediagram with the following shown on the diagram: N representing now or today, T for tomorrow, and T + 1 for the day after tomorrow, Y for yesterday, and Y  1 for the day before yesterday. Count 6 days to the right of Y  1 (the day before yesterday). Mark that day in the diagram as H for Thursday. Count back 2 days to T + 1 (the day after tomorrow). That day is Tuesday. 2) 3) The number of coins must be a multiple of 30. The multiples of 30 are 30, 60, 90, 120, 150, and so on. The smallest of these multiples that leaves a remainder of 1 when divided by 7 is 120.
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